1.

The % by volume of C_(4)H_(10) in a gaseous mixture of C_(4)H_(10), CH_(4) and CO_(2) is 40. When 200 ml of this mixture is burnt completely in excess of O_(2) and then pass through aq. KOH then volume contraction will be -

Answer»

220 ml
340 ml
440 ml
560 ml

Solution :`ubrace(C_(4)H_(10), CH_(4),CO_(2))_("200 mL")`
`C_(4)H_(10) = 0.4 xx 200 = 80 ml`
`CH_(4) = x ml`
`CO_(2) = (120 - x) ml`
`C_(4)H_(10) + (13)/(2) O_(2) rarr 4CO_(2) + 5H_(2)O`
`{:(80 ml,,"320 ml",),(CH_(4) + 2O_(2),rarr,CO_(2) + 2H_(2)O,),(x ml,,x ml,):}`
Total `CO_(2) = 320 + x + 120 - x`
`= 440 ml`


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