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The Boyle temperature of a van der Waal gas is `-246^(@)C`. Its critical temperature on absolute temperature scale is :A. `5K`B. `7K`C. `8K`D. `10K` |
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Answer» Correct Answer - C The Boyle temperature of a vander Waal …………. `T_(c ) = (8//27)xxT_(B)= (8//27)xx27K = 8K` |
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