The bond enthalpy of ___________molecule is 435.8 kJ mol^-1.(a) Hydrogen(b) Oxygen(c) Nitrogen(d) HeliumThis question was addressed to me by my college professor while I was bunking the class.This question is from Valence Bond Theory in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

The bond enthalpy of ___________molecule is 435.8 kJ mol^-1.(a) Hydrog

1.	The bond enthalpy of ___________molecule is 435.8 kJ mol^-1.(a) Hydrogen(b) Oxygen(c) Nitrogen(d) HeliumThis question was addressed to me by my college professor while I was bunking the class.This question is from Valence Bond Theory in section Chemical Bonding and Molecular Structure of Chemistry – Class 11
Answer» Correct option is (a) Hydrogen Easy explanation: The amount of energy that is required to break a chemical BOND in a MOLECULE into INDIVIDUAL atoms is known as bond ENTHALPY. 435.8 kJ mol^-1 is required to DISSOCIATE a hydrogen molecule into two hydrogen atoms.

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