The bond enthalpy of H2O and OH are 502 KJ mol^-1 and 427 KKJ mol^-1. Then what is the average bond enthalpy?(a) 502 KJ mol^-1(b) 464.5 KJ mol^-1(c) 427 KJ mol^-1(d) 75 KJ mol^-1The question was posed to me in exam.Question is from Bond Parameters in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

The bond enthalpy of H2O and OH are 502 KJ mol^-1 and 427 KKJ mol^-1.

1.	The bond enthalpy of H2O and OH are 502 KJ mol^-1 and 427 KKJ mol^-1. Then what is the average bond enthalpy?(a) 502 KJ mol^-1(b) 464.5 KJ mol^-1(c) 427 KJ mol^-1(d) 75 KJ mol^-1The question was posed to me in exam.Question is from Bond Parameters in division Chemical Bonding and Molecular Structure of Chemistry – Class 11
Answer» Right answer is (b) 464.5 KJ mol^-1 The EXPLANATION is: We KNOW that H2O(G) → H(g) + OH(g); ΔH1 = 502 kJ mol^-1 and OH(g) → H(g) + O(g); ΔH2 = 427 kJ mol^-1. So the average bond ENTHALPY is given by their mean that is 427 + 502/2 = 464.5 KJ mol^-1. This method is used for polyatomic molecules like water.

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