The bond enthalpy of H2(g) is 436 kJ/mol and that of N2(g) is 941.3 kJ – InterviewSolution

1.	The bond enthalpy of H2(g) is 436 kJ/mol and that of N2(g) is 941.3 kJ/mol. Calculate the average bond enthalpy of an N−H bond in ammonia.ΔH∘f(NH3)=−46 kJ/mol
Answer» The bond enthalpy of $H_{2} (g)$ is $436 kJ/mol$ and that of $N_{2} (g)$ is $941.3 kJ/mol$ . Calculate the average bond enthalpy of an $N - H$ bond in ammonia. $Δ H_{f}^{\circ} (N H_{3}) = - 46 kJ/mol$

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