1.

the bond dissociation energies of gasseous H_(2) , Cl_(2) and HCl are 104 .58and 103 kcal respectively . The enthaply of formation of HCl gas would be

Answer»

`-44 kcal`
44 kcal
`-22 kcal `
22 kcal

Solution :`1/2H_(2)+1/2Cl_(2)toHCl`
`DeltaH=[1/2RE(H_(2))+1/2BE(Cl_(2))]-BE(HCL)`
`[(1/2xx104)+(1/2xx58)]-103=-22kcal`


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