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The bob of simple pendulum is held in the horizantal position calculate the speed of the bob of pendulum at the lowest position B when released and the length of pendulum is 0.5 meter and assume that there is no loss of energy ​

Answer»

Increase in potential Energy of BOB =mgΔh where m is mass of bob, g=9.81 ms−2 is acceleration due to gravity and Δh is change in height of bob.As shown in the FIGURE, Δh=L−Lcosθ . INSERTING given VALUES we getWork DONE on the bob =0.5×9.81(20−20 cos30∘) ⇒ Work done on the bob =0.5×9.81×20(1−√32)=13.1 J



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