The binding energy of deuteron (21H) is 1.15 MeV per nucleon and an al – InterviewSolution

1.	The binding energy of deuteron (21H) is 1.15 MeV per nucleon and an alpha particle (42He) has a binding energy of 7.1 MeV per nucleon. Then in the reaction 21H+21H→42He+Q the energy Q released is
Answer» The binding energy of deuteron $(_{1}^{2} H)$ is 1.15 MeV per nucleon and an alpha particle $(_{2}^{4} H e)$ has a binding energy of 7.1 MeV per nucleon. Then in the reaction $_{1}^{2} H +_{1}^{2} H \to_{2}^{4} H e + Q$ the energy Q released is

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