The base of an isosceles triangle measures 24 cm and its area is `192 – InterviewSolution

1.	The base of an isosceles triangle measures 24 cm and its area is `192 cm^(2)` , Find its perimeter.
Answer» Here , base ,b=24 cm am and let each equal side be a cm . Then , `area =(1)/(4)b sqrt(4a^(2)-b^(2))sq " units"=(1)/(4) xx24xxsqrt(4a^(2)-576)cm^(2)` `= 12xxsqrt(a^(2)-144)cm^(2),` `"but area " =192 cm^(2) ["given "]`. `therefore 12xxsqrt(a^(2)-144)=192implies sqrt(a^(2)-144)=16` `implies a^(2) -144 = 256implies a^(2) = 400 implies a=20.` `therefore ` perimeter of the triangle `=(2a+b)cm ` `=(2xx20 +24)cm =64 cm.`

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