the base of an isosceles triangle is 10 cm and one of its equal side 1

1.	the base of an isosceles triangle is 10 cm and one of its equal side 13 cm .find its area using heron's formula
Answer» Answer: SEMIPERIMETER=(13+13+10)/2 36/2=18cm Area=√s(s-a)(s-b)(s-c) √18(5)(5)(8) =√(2)(3)(3)(5)(5)(2)(2)(2) =223*5 =60cm² Hope you find my answer helpful Please mark as brainliest

the base of an isosceles triangle is 10 cm and one of its equal side 13 cm .find its area using heron's formula

Answer»

Answer:

SEMIPERIMETER=(13+13+10)/2

36/2=18cm

Area=√s(s-a)(s-b)(s-c)

√18(5)(5)(8)

=√(2)(3)(3)(5)(5)(2)(2)(2)

=2*2*3*5

=60cm²

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the base of an isosceles triangle is 10 cm and one of its equal side 13 cm .find its area using heron's formula ​

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the base of an isosceles triangle is 10 cm and one of its equal side 13 cm .find its area using heron's formula