The base of a triangular field is three times its altitude. If the cos

1.	The base of a triangular field is three times its altitude. If the cost of levelling the field atmetre is 76588, find its base and height.3050 per sq
Answer» Let the altitude of the triangular field be h. then base of the triangle will be 3h. Area of triangle =1/2×base×height. =1/2×3h×h =3/2h^2 cost of levelling =6588 =3/2×h^2×30.50=6588 =h^2=6588/45.76 h^2=143.96 h=11.99 so altitude of triangle=11. 99m base =11. 99×3=35.97m

The base of a triangular field is three times its altitude. If the cost of levelling the field atmetre is 76588, find its base and height.3050 per sq

Answer»

Let the altitude of the triangular field be h. then base of the triangle will be 3h.

Area of triangle =1/2×base×height.

=1/2×3h×h

=3/2h^2

cost of levelling =6588

=3/2×h^2×30.50=6588

=h^2=6588/45.76

h^2=143.96

h=11.99

so altitude of triangle=11. 99m

base =11. 99×3=35.97m