The base area of cylinder is 20 square cm and the height is 5 cm.what

1.	The base area of cylinder is 20 square cm and the height is 5 cm.what is the volume of cylinder
Answer» Given Base area of Cylinder = 20 cm² HEIGHT of Cylinder = 5 cm Explanation: ✮Firstly We've to FIND the Radius of the Volume using formula of area of Circle as the Base of the Cylinder is in Circular SHAPE:- $\dag {\pink{\boxed{\underline{\sf{ Area_{(Circle )} = πr^2 }}}}} \\ \\ \colon\implies{\sf{ 20 = \dfrac{22}{7} \times (r)^2 }} \\ \\ \\ \colon\implies{\sf{ \dfrac{140}{22} = (r)^2 }} \\ \\ \\ \colon\implies{\sf{ r^2 = 6.36 }} \\ \\ \\ \colon\implies{\sf{ r = \sqrt{6.36} \mapsto 2.5 \ cm \ \ \ (approx.) }} \\$ ✮Now, we can find the Volume of the Cylinder using height and Radius of the Cylinder that we've as:- $\dag{\pink{\boxed{\underline{\sf{ Volume_{(Cylinder)} = πr^2h }}}}} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \dfrac{22}{7} \times (2.5)^2 \times 5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \dfrac{22}{7} \times 6.5 \times 5}} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \cancel{ \dfrac{22}{7} } \times 32.5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = 3.14 \times 32.5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = 102.05 \ cm^3 }} \\$ Hence, The Volume of the Cylinder will be 102.05 cm³.

The base area of cylinder is 20 square cm and the height is 5 cm.what is the volume of cylinder

Answer»

Given

Base area of Cylinder = 20 cm²
HEIGHT of Cylinder = 5 cm

Explanation:

✮Firstly We've to FIND the Radius of the Volume using formula of area of Circle as the Base of the Cylinder is in Circular SHAPE:-

$\dag {\pink{\boxed{\underline{\sf{ Area_{(Circle )} = πr^2 }}}}} \\ \\ \colon\implies{\sf{ 20 = \dfrac{22}{7} \times (r)^2 }} \\ \\ \\ \colon\implies{\sf{ \dfrac{140}{22} = (r)^2 }} \\ \\ \\ \colon\implies{\sf{ r^2 = 6.36 }} \\ \\ \\ \colon\implies{\sf{ r = \sqrt{6.36} \mapsto 2.5 \ cm \ \ \ (approx.) }} \\$

✮Now, we can find the Volume of the Cylinder using height and Radius of the Cylinder that we've as:-

$\dag{\pink{\boxed{\underline{\sf{ Volume_{(Cylinder)} = πr^2h }}}}} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \dfrac{22}{7} \times (2.5)^2 \times 5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \dfrac{22}{7} \times 6.5 \times 5}} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \cancel{ \dfrac{22}{7} } \times 32.5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = 3.14 \times 32.5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = 102.05 \ cm^3 }} \\$