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The balancing lengths on a potentiometer wire are `800cm` and `600cm` when two cells of emfs `E_(1)` and `E_(2)` are connected in the secondary circuit first to help each other and next to oppose each other, then `(E_(1))/(E_(2))=`A. `1//11`B. `14//11`C. `7//1`D. `4//3` |
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Answer» Correct Answer - C `(E_(1)+E_(2))/(E_(1)-E_(2))=(l_(1))/(l_(2))implies(E_(1))/(E_(2))=(l_(1)+l_(2))/(l_(1)-l_(2))` |
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