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The axis of the parabola `9y^2-16x-12y-57 = 0` isA. `3y=2`B. `x+3y=3`C. `2x=3`D. `y=3` |
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Answer» Correct Answer - A We have `9y^(2)-16x-12y-57=0` `rArr" "y^(2)-4/3y=16/9x+57/9` `rArr" "(y-2/3)^(2)=(16x)/9+61/9rArr(y-2/3)^(2)=16/9(x+61/16)` The axis of this parabola is `y=2/3=0rArr3y=2" "|because" Axis of "y^(2)="4ax is y=0" |` |
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