1.

The average value of rotational kinetic energy of 1 mole of Oxygen gas at temperature t will be ?

Answer»

O₂ is a diatomic molecule . HENCE , there are five degree of freedom for 1 MOLE of O₂ gas .In which 3 translational and 2 ROTATIONAL .
∴ degree of freedom for 1 mole of O₂ gas , f = 2 [ for rotational motion ]
We KNOW,
Average Rotational Kinetic energy = \frac{f}{2}\bold{RT}
Here f is degree of freedom for rotational motion.
∴ average Rotational Kinetic energy = 2/2 RT = RT



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