1.

The average value of rotational kinetic energy of 1 mole of Oxygen gas at temperature t will be

Answer»

O₂ is a DIATOMIC molecule . Hence , there are five DEGREE of freedom for 1 MOLE of O₂ gas .In which 3 translational and 2 rotational .
∴ degree of freedom for 1 mole of O₂ gas , f = 2 [ for rotational motion ]
We know,
Average Rotational Kinetic energy = \bold{\frac{f}{2}<klux>RT</klux>}
Here f is degree of freedom for rotational motion.
∴ average Rotational Kinetic energy = 2/2 RT = RT



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