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The average resisting force that must act on a 5 kg mass to reduce its speed from 65cm/s to 15cm/s in 0.2s isA) 12.5 NB) 25 NC) 50 ND) 100 N |
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Answer» A) 12.5 N Explanations: Fdt = mv-mu from work energy theorem F = m( v-u)/dt = 5(65-15)/0.2*100 = 5*50/20 = 12.5 N |
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