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The average of five numbers is 46. If the average of the last 4 numbers is 45,then which is the first number ? |
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Answer» Answer: let the numbers be a,b,c,d,e,f Step-by-step explanation: given a+b+c+d+e/5 =46 _equation 1 then a+b+c+d+e=230 and given b+c+d+e/4=45 b+c+d+e=180_equation 2 then subtracting EQUATION 2 from equation 1 a+b+c+d+e-b-c-d-e=230-180 then a=50 hence first NUMBER is 50 |
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