Saved Bookmarks
| 1. |
The average atomic mass of copper is `63.5`. It exists as two isotopes which are `._(29)^(63)Cu and ._(29)^(65)Cu`. Calculate the percentage of each isotope present in it. |
|
Answer» Let the percentage of `._(29)^(63)Cu` isotope `= x` `:.` The percentage of `._(29)^(65) Cu` isotope `= 100 -x` From the above data, the average atomic mass of `Cu=(63xxx)/(100)+(65xx(100-x))/(100)` But the given average atomic mass of `Cu = 63.5` `:. (63xxx)/(100)+(65xx(100-x))/(100)=63.5` `63x+6500-65x=6350" "2x=6350-6500=-150` `2x=150orx=75` `:.` Percentage of `._(29)&(63)Cu` isotope `= 75 %` , Percentage of `._(29)^(65) Cu` isotope `= 25 %`. |
|