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The average age of three boys is 15 years and their ages are in tje ratio 3:5:7. Find the age of the youngest boy |
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Answer» let the age of first boy =3x let the age of second boy =5x let the age of THIRD boy = 7x ACCORDING TO THE QUESTION = 3x+ 5x+ 7x = 15 =15x=15 therefore, x = 15/15 x= 1 hence , the age of first boy = 3x =3×1 =3 years the age of second boy = 5x = 5×1 = 5 yrs the age of third boy = 7x =7×1 = 7years so, the age of youngest boy = 3 years |
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