1.

The average age of three boys is 15 years and their ages are in tje ratio 3:5:7. Find the age of the youngest boy

Answer»

ANSWER:

let the age of first boy =3x

let the age of second boy =5x

let the age of THIRD boy = 7x

ACCORDING TO THE QUESTION

= 3x+ 5x+ 7x = 15

=15x=15

therefore, x = 15/15

x= 1

hence , the age of first boy = 3x =3×1 =3 years

the age of second boy = 5x = 5×1 = 5 yrs

the age of third boy = 7x =7×1 = 7years

so, the age of youngest boy = 3 years



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