The average age of five students is 12 years and the average age of fi

1.	The average age of five students is 12 years and the average age of first four is 13 years. Find the age of the fifth student in arithmetic calculation.
Answer» Let 5 students be a , a+d , a+2d , a+3d , a+4d ..... According to the question ,,,,, $\frac{a + a + d + a + 2d + a + 3d + a + \: 4d}{2}= 12 \\ \\ \frac{ 5a + 10d }{2}= 12 \\ \\by \: cross \: multiplying \\ \\ 5a + 10d = 24 \: \: \: \: - - - - - -(<klux>1</klux>) \\ \\$ $\frac{a + a + d + a + 2d + a + 3d}{2} = 13 \\ \\ \frac{4a + 6d}{2} = 13 \\ \\ by \: cross \: multiplying \\ \\ 4a + 6d = 26 \: \: - - - - - - (2)$ MULTIPLY 6 to (1) and 10 to (2)

The average age of five students is 12 years and the average age of first four is 13 years. Find the age of the fifth student in arithmetic calculation.

Answer»

Let 5 students be a , a+d , a+2d , a+3d , a+4d .....

According to the question ,,,,,

$\frac{a + a + d + a + 2d + a + 3d + a + \: 4d}{2}= 12 \\ \\ \frac{ 5a + 10d }{2}= 12 \\ \\by \: cross \: multiplying \\ \\ 5a + 10d = 24 \: \: \: \: - - - - - -(<klux>1</klux>) \\ \\$

$\frac{a + a + d + a + 2d + a + 3d}{2} = 13 \\ \\ \frac{4a + 6d}{2} = 13 \\ \\ by \: cross \: multiplying \\ \\ 4a + 6d = 26 \: \: - - - - - - (2)$

MULTIPLY 6 to (1) and 10 to (2)

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The average age of five students is 12 years and the average age of first four is 13 years. Find the age of the fifth student in arithmetic calculation.

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