The avarge boys of 15 years. If their ages aur in the ratio 3:5:7 find

1.	The avarge boys of 15 years. If their ages aur in the ratio 3:5:7 find the age of youngest boy?
Answer» Let their ages be 'X'. It is given that the average of the ages of the 3 BOYS is 15. The ratio of their is 3:5:7. => (3x+5x+7x)/3 = 15 => 15x/3 = 15 => 5x = 15 => x = 3 There ages will be: 3x = 3(3) = 9 5x = 5(3) = 15 7x = 7(3) = 21 Therefore, the age of the youngest BOY is 9.

The avarge boys of 15 years. If their ages aur in the ratio 3:5:7 find the age of youngest boy?

Answer»

Let their ages be 'X'.

It is given that the average of the ages of the 3 BOYS is 15.

The ratio of their is 3:5:7.

=> (3x+5x+7x)/3 = 15

=> 15x/3 = 15

=> 5x = 15

=> x = 3

There ages will be:

3x = 3(3) = 9

5x = 5(3) = 15

7x = 7(3) = 21

Therefore, the age of the youngest BOY is 9.

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The avarge boys of 15 years. If their ages aur in the ratio 3:5:7 find the age of youngest boy?

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