1.

The audible range of a human ear is 20 Hz to 20 kHz. Convert this into corresponding wavelength range. The speed of sound at ordinary temperature is `340 m//s`.

Answer» Here, speed of sound in air, `v = 340 m//s`
lowest frequency, `v_1 = 20 Hz`
highest frequency, `v_2 = 20 kHz = 20 xx 10^2 Hz`
Clearly, upper limit of wavelength, i.e., `lamda_1 = (v)/(v_1) = (340)/(20) = 17 m`
and lower limit of wavelength, i.e., `lamda_2 = (v)/(v_2) = (340)/(20 xx 10^3) = 0.017 m`
Thus, the audible wavelength range is 0.017 m to 17 m.


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