The atomic spectrum of Li2+ ion arises due to the transition of an ele – InterviewSolution

1.	The atomic spectrum of Li2+ ion arises due to the transition of an electron from n2 to n1. If n2+n1=4 and n2−n1=2. The wavenumber of 3rd line of this series in Li2+ ion is found to be x×135 cm−1. Find the value of x. (Rydberg Constant(RH)≈109600 cm−1)
Answer» The atomic spectrum of $L i^{2 +}$ ion arises due to the transition of an electron from $n_{2}$ to $n_{1}$ . If $n_{2} + n_{1} = 4$ and $n_{2} - n_{1} = 2$ . The wavenumber of $3^{r d}$ line of this series in $L i^{2 +}$ ion is found to be $x \times 135 c m^{- 1}$ . Find the value of x. $(R y d b e r g C o n s t a n t (R_{H}) \approx 109600 c m^{- 1})$

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