The asymptote of the hyperbola x2a2−y2b2=1 forms a triangle with an – InterviewSolution

1.	The asymptote of the hyperbola x2a2−y2b2=1 forms a triangle with any tangent to the hyperbola. The area of such triangle formed is a2tanλ , where λ∈(0,π2) then its eccentricity is
Answer» The asymptote of the hyperbola $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$ forms a triangle with any tangent to the hyperbola. The area of such triangle formed is $a^{2} tan λ$ , where $λ \in (0, \frac{π}{2})$ then its eccentricity is

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