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The arrangement shown consists of three elements. (i) A thin rod of charge `-3.0 mu C` that froms a full circule of radius `6.0 cm`. (ii) A second thin rod of charge `2.0 mu C` that forms a circular are of radius `4.0 cm` and concentric with the full circle, subtending an angle of `90^(@)` at the centre of the full circle. (iii) an electric dipole with a dipole moment that is perpendicular to a radial line and has magnitude `1.28xx10^(-21) C-m`. Find the net electric potential in volts at the centre. |
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Answer» Potential due to dipole at the centre of the circle is zero. Potentials due to charge on circle `=V_(1)=(K.(-3xx10^(-6)))/(6xx10^(-2))` Potential due to are `V_(2)=(K.(2xx10^(-6)))/(4xx10^(-2))` Net potential `=V_(1)+V_(2)=0` |
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