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The areas of two similar triangles are 12 and 48. if the height of smaller one is 2.1 then find corresponding height of bigger triangle |
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Answer» "GIVEN, Area of two similar triangles = 12 cm², 48 cm². Area of bigger triangle = 48 cm² Area of smaller triangle = 12 cm² We know that, Ratio of the areas of two similar is equal to square of the ratio of corresponding heights or ALTITUDES. Given, HEIGHT of smaller triangle =2.1 CM. Area (Bigger Triangle)/Area (Smaller Triangle) = (Height of bigger triangle) ^2/ (Height of smaller triangle) ^2 48/12 = (Height of bigger triangle) ^2/2.1² 4 = (Height of the triangle) ² / 4.41 √ (4 * 4.41) = Height of the bigger triangle Height of the bigger triangle = 2 * 2.1 = 4.2 cm. " |
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