Saved Bookmarks
| 1. |
The areas of two similar triangles ABC and DEF are 169 cm² and 144 cm² respectively. If the longest side of the larger triangle is 13 cm, the longest side of the smaller triangle is ? |
|
Answer» GIVEN: Area of two similar TRIANGLES is 169cm² and 121cm². The longest side of the larger triangle = 26 cm. We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides. ar(larger∆)/ar(smaller ∆) = (side of the larger triangle/ side of the smaller triangle)² 169/121 = (side of the larger triangle/ side of the smaller triangle)² On taking square ROOT on both sides, √169/121 = √(longest side of the larger triangle/ longest side of the smaller triangle)² 13/11 = longest side of the larger triangle/ longest side of the smaller triangle 13/11 = 26/longest side of the smaller triangle longest Side of the smaller triangle = ( 11×26)/13 = 11 × 2 = 22 cm longest Side of the smaller triangle = 22 cm Hence, the longest side of the smaller triangle is 22 cm. HOPE THIS ANSWER WILL HELP YOU ❤❤ |
|