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The areas of the two similar triangles are in the ratio of the square of the corresponding medians. |
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Answer» BD=DC=1/2BC QS=SR=1/2QR `(BD)/(QS)=(DC)/(SR)=(BC)/(QR)` -(1)`/_ABC`~`/_PQR`(AAA) `(AB)/(PQ)=(BC)/(QR)=(CA)/(RP)` `angleB=angleQ` `/_ABC`~`/_PQS` |
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