The area of trapezium is 476. The lengths of the parallel sides are 10

1.	The area of trapezium is 476. The lengths of the parallel sides are 10cm and 46 cm. Find the distance between them
Answer» ${\orange{\underbrace{\overbrace{\bf{ Solution :}}}}}\\$ $\text{[math]}$ the distance between PARALLEL sides of TRAPEZIUM are HEIGHT of trapezium. $\text{[math]}$ Let, the height be x area of trapezium = ${476cm}^{2}$ 1/2 × height × sum of parllel SIDE = ${476cm}^{2}$ 1/2 × x × 10CM + 46cm = ${476cm}^{2}$ 1/2 × x × 56cm = ${476cm}^{2}$ 1/2 × 56cmx = ${476cm}^{2}$ 28cmx = ${476cm}^{2}$ x = $\frac{{476cm}^{2}}{ 28cm}$ x = $\frac{{\cancel{476cm}}^{2}}{ \cancel{28cm}}$ x = $17cm$ height of trapezium is 17cm. it means that distance between parallel side is 17cm ${\blue{\underbrace{\overbrace{\bf{ Answer : 17cm}}}}}\\$