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Area Of A Trapezium Is Equal To 30.8cm sqr We Need To Find It's Height If Parallel Sides Are 4.8cm & 6.4cm.



# Now To Find It's Height Follow The Simple Steps....

It's Given That

Area of Trapezium = 30.8cm sqr

Length First Parallel Side ( a ) = 4.8cm

And

Length of Second Parallel Sidthe e = 6.4cm

Now LET The Length of Height = X

Now we Know That Formula To Find Area Of Trapezium Is

1/2 ( a + B ) × Height (h)

Here (a) & (b) Are The Parallel Sides Of Trapezium..

So Now Putting Values Of (a) , (b) & (h) In the Formula We Have ....⤵️

1/2 × ( 4.8cm + 6.4cm) × (x)

Now According To Question The Area Of Trapezium Is Equal To

30.8 (cm)^2

So Now Putting This In RHS Of The Formula We Have....

1/2 ( 4.8cm+6.4cm) × (x) = 30.8(cm)^2

Now Finding Sum Of Bracket We Have...

1/2 (11.2cm) × (X) = 30.8 (cm)^2

Now Finding PRODUCT Of The Terms In LHS We Have ➡️

5.6cm(X) = 30.8(cm)^2

Now Taking 5.6cm To RHS We Have.....

X = 30.8/5.6

That Is ➡️

X = 5.5cm

Therefore Height Of The Trapezium Is Equal To

Height = X = 5.5 cm





Thought Of The Day .....

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