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the area of the triangle whose vertices are i, alpha, beta, where i= root -1 and alpha , beta are the non real cube roots of unity is |
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Answer» The vertices of the triangle formed by the cube roots of unity = 1 , ω, ω² . the vertices in the complex plane are described by : 1 = (1, 0) ω = (-1/2 , √3/2 ) ω² = ( -1/2 , -√3/2) The side of this equilateral triangle is = √3 Altitude of the triangle is = √3/2 * √3 = 3/2 So area of triangle = 1/2 * 3/2 * √3 = 3√3 / 4 |
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