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The area of the square having diagonal of length d' is given by2. |
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Answer» Answer: 4 Step-by-step EXPLANATION: Let the square be QUADRILATERAL ABCD Let Triangle ABC have a RIGHT angle at B So Thus by Pythagoras THEOREM : In Δ ABC (AC)² = (AB)² + (BC)² (2)² = (AB)² + (BC)² 4 = (AB)² + (BC)² AB=BC=x 4 = x² √4 = x 2 = x So Thus The Side of the Square is 2 So Thus the Area is = Side * Side = 2 * 2 = 4 |
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