The area of the region above the x− axis bounded by the curve y=tanx, 0≤x≤π2 and the tangent to the curve at x=π4 is −a(a+lna), then 1a is equal to

The area of the region above the x− axis bounded by the curve y=tanx

1.	The area of the region above the x− axis bounded by the curve y=tanx, 0≤x≤π2 and the tangent to the curve at x=π4 is −a(a+lna), then 1a is equal to
Answer» The area of the region above the $x -$ axis bounded by the curve $y = tan x, 0 \leq x \leq \frac{π}{2}$ and the tangent to the curve at $x = \frac{π}{4}$ is $- a (a + ln a),$ then $\frac{1}{a}$ is equal to