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The area of the quadrilateral formedby y-2x, y-4x and the coordinateaxes is(A) 8(B) 6(C) 4(D) 12 |
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Answer» The given lines are parallel lines. Let the line y=2-x intersect the x-axis and y-axis in A and B respectively. Hence OA=OB=2 unit. (O is the origin). Let the line y=4-x intersect the x-axis and y-axis in C and D respectively. Hence OC=OD=4 units Required area=Area(OCD)-Area(OAB) Required area=1/2(OC.OD)-1/2(OA.OB) Required area=1/2(4*4)-1/2(2*2) Hence Required Area= 8-2 = 6 sq.units |
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