1.

The area of the circular base of a cone is 616 cm2 and its height is 48 cm. Find its whole surface area. [take π = 22/7 ]

Answer»

We have height of circular cone is h = 48 cm. 

And the area of the circular base of the cone is 616 cm2

Let the radius of base of circular cone is r cm.

∴ πr2 = 616

⇒ r2 = \(\frac{616}{\pi}\) 

= \(\frac{616}{22}\) × 7 

= 28 × 7 

= 72 × 22 

⇒ r = 7 × 2 = 14 cm.

∴ Radius of the base of cone is r = 14 cm.

The slant height of the cone is l = \(\sqrt{r^2+h^2}\)

 = \(\sqrt{14^2+48^2}\)

 = \(\sqrt{196+2304}\)

 = \(\sqrt{2500}\)

= 50cm.

Now,

The whole surface area of cone = πr(r + l)

= \(\frac{22}{7}\) × 14(14 + 50) 

= 22 × 2 × 64 

= 2816 cm2.

∴ The whole surface area of the cone is 2816 cm2.



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