the area of the base of a tent in the form of a right circular cone is

1.	the area of the base of a tent in the form of a right circular cone is 13.86 sq.metre. To make the tent a tripol of rupees 5775 is required and the price of 1 square metre of tripol is rupees 250. Find the height of the tent.
Answer» Step-by-step explanation: Radius of base of cylindrical portion=14m Height of cylindrical portion=3m Curved SURFACE area of cylindrical PART=2× $22 \: \times 14 \: \times 3 \: \ \\7$ Height of CONICAL part=13.5−3=10.5m For conical part:r=14m,h=10.5m 1= $\sqrt{(14) {}^{2} \: + (10.5) {}^{2} }$ = $\sqrt{306.25}$ 1=17.5 CSA of conical part= πrl = $\frac{22}{7} \times 14 \times 17.5 = 770m {}^{2}$ ∴Total area to be PAINTED= (264+770)m² = 1034m² Cost of painting=Rs. (1034×2)=Rs. 2068 xXitzMeAngelXx

the area of the base of a tent in the form of a right circular cone is 13.86 sq.metre. To make the tent a tripol of rupees 5775 is required and the price of 1 square metre of tripol is rupees 250. Find the height of the tent.

Answer»

Step-by-step explanation:

Radius of base of cylindrical portion=14m

Height of cylindrical portion=3m

Curved SURFACE area of cylindrical PART=2×

$22 \: \times 14 \: \times 3 \: \ \\7$

Height of CONICAL part=13.5−3=10.5m

For conical part:r=14m,h=10.5m

$\sqrt{(14) {}^{2} \: + (10.5) {}^{2} }$

$\sqrt{306.25}$

1=17.5

CSA of conical part= πrl =

$\frac{22}{7} \times 14 \times 17.5 = 770m {}^{2}$

∴Total area to be PAINTED= (264+770)m² = 1034m²

Cost of painting=Rs. (1034×2)=Rs. 2068

xXitzMeAngelXx

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the area of the base of a tent in the form of a right circular cone is 13.86 sq.metre. To make the tent a tripol of rupees 5775 is required and the price of 1 square metre of tripol is rupees 250. Find the height of the tent.​

xXitzMeAngelXx

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the area of the base of a tent in the form of a right circular cone is 13.86 sq.metre. To make the tent a tripol of rupees 5775 is required and the price of 1 square metre of tripol is rupees 250. Find the height of the tent.