Saved Bookmarks
| 1. |
the area of shaded portion only, if OA-OBOCOD14 cm. |
|
Answer» Given: OA=OB=OC=OD=14CM Angles DOB, AOD, COB and AOC are 90 degrees each ( quadrants)To find the area of the shaded region.The radius =7cmArea of a semi circle = 22/7*7*7*1/2 = 77sq. cm Area of a quadrant = 90/360*22/7*14*14 = 154 sq. cm Therefore, area of shaded region==2(ar. semicircle) + 2( ar. quadrant- ar. semicircle)=2 * 77 + 2 * (154 - 77) sq. cm= 154 + 154= 308 sq. cm |
|