1.

The area of cross-section of railway track is 0.01 m^(2). The temperature variation is 10^(@)C. Coefficient of linear expansion of steel =10^(-5)//""^(@)C. (Young's modulus of steel = 10^(11) Nm^(-2)). Calculate the energy stored per meter in the track.

Answer»

Solution :LET `alpha`= Coefficient of LINEAR expansion.
`:.` Elastic energy `=(1)/(2) xx "stress " xx "strain " xx "volume"`
or `U= (1)/(2) xx (Y xx "strain") xx` strain `xx` volume
or `U= (1 xx Y xx ("strain")^(2) xx "volume")/(2)`
`alpha= (l)/(L xx t) = ("strain")/(t)`
`:. alpha= ("CHANGE in LENGTH")/("original length" xx "temperature change")`
or strain `= alpha t`
`:. U = (Y xx alpha^(2) t^(2) xx ("AREA" xx "length"))/(2)`
or `U= (10^(11)xx (10^(-5))^(2) xx (10)^(2) xx 0.01xx 1)/(2) = 5J`
`:.` Energy stored `=5J`


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