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The area of a triangle with vertices A(3,0),B(7,0) and C(8,4) isA. 14B. 28C. 8D. 6 |
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Answer» Correct Answer - c Area of `triangleABC` whose Vertices A `-=(x_(1),y_(1)),B-=(x_(2),y_(2))and C-=(x_(3),y_(3))` are given by `triangle` `=|(1)/(2)[x_(1)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(3)(y_(1)-y_(2))]|` Here , `x_(1)=3,y_(1)=0,x_(2)=7,y_(2)=0x_(3)=8 and y_(3)=4` `:.` triangle=|(1)/(2)[3(0-4)+7(4-0)+8(0-0)]|=| (1)/(2)(-12+28+0)|(1)/(2)(16)|=8` Hence , the requirred area of `triangleABC` is 8. |
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