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The area of a trapezium of height 8m is 208 m.sq. sum of its parallel sides is |
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Answer» Given: Area of trapezium= 248 m² Height (h)= 8 m Let the one parallel SIDE be= x m Other parallel side =( x-4) m Area of trapezium = 1/2 ( sum of parallel SIDES) × height 248 = 1/2 ( X+ X- 4)× 8 248 = (2x - 4) × 4 248/4 = 2x-4 62 = 2x-4 62+4= 2x 66= 2x X= 66/2 X= 33 One parallel side (X)= 33 m Other parallel side(x-4)= 33-4= 29 m ========================================= |
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