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The area of a trapezium is 248 sq.m and its height is 8 m. If one of the parallel sideis smaller than the other by 4 m, find two parallel sides.2 altitude is 10 dm |
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Answer» Given: AREA of trapezium= 248 m² Height (h)= 8 m Let the one PARALLEL side be= x m Other parallel side =( x-4) m Area of trapezium = 1/2 ( SUM of parallel sides) × height 248 = 1/2 ( X+ X- 4)× 8 248 = (2x - 4) × 4 248/4 = 2x-4 62 = 2x-4 62+4= 2x 66= 2x X= 66/2 X= 33 One parallel side (X)= 33 m Other parallel side(x-4)= 33-4= 29 m
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