1.

The area of a trapezium is 248 sq.m and its height is 8 m. If one of the parallel sideis smaller than the other by 4 m, find two parallel sides.2 altitude is 10 dm​

Answer»

Given:

AREA of trapezium= 248 m²

Height (h)= 8 m

Let the one PARALLEL side be= x m

Other parallel side =( x-4) m

Area of trapezium = 1/2 ( SUM of parallel sides) × height

248 = 1/2 ( X+ X- 4)× 8

248 = (2x - 4) × 4

248/4 = 2x-4

62 = 2x-4

62+4= 2x

66= 2x

X= 66/2

X= 33

One parallel side (X)= 33 m

Other parallel side(x-4)= 33-4= 29 m

 



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