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The area of a trapezium is 248 sq.m and its height is 8 m. If one of the parallel side is smaller than the other by 4 m, find two parallel sides.2 altitude is 10 dm |
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Answer» N:
Area of trapezium= 248 m² Height (H)= 8 m
Let the one parallel side be= x m Other parallel side =( x-4) m
Area of trapezium = 1/2 ( sum of parallel sides) × height
248 = 1/2 ( X+ X- 4)× 8
248 = (2X - 4) × 4
248/4 = 2x-4
62 = 2x-4
62+4= 2x
66= 2x
X= 66/2
X= 33
One parallel side (X)= 33 m
Other parallel side(x-4)= 33-4= 29 m
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