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The area of a trapezium is 1080 cm2. If the lengths of its parallel sides be 55 cm and 35 cm, find the distance between them. |
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Answer» Given Length of parallel sides is 55cm and 35 cm Area of trapezium= 1080 cm2 Let Height (h) = y cm We know that area of trapezium is \(\frac{1}{2}\)× (sum of parallel sides) × height Therefore Area of trapezium is \(\frac{1}{2}\)× (55 + 35) × y =1080 cm2. \(\therefore \frac{1}{2}\)× (90) × y =1080 ⇒ 45 × y =1080 ⇒ y \(=\frac{1080}{22}=24\) ∴ Distance between the parallel lines is 24 cm. |
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