The area of a square is 1600meter square. Find the area of the rectang

1.	The area of a square is 1600meter square. Find the area of the rectangle whose breadth is the same as that of the square and length is 10m more than its breadth.
Answer» $\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$ The area of a SQUARE is 1600meter square. FIND the area of the rectangle whose breadth is the same as that of the square and length is 10M more than it's breadth. $\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$ $\Large{\underline{\mathfrak{\bf{Given}}}}$ Area of square = 1600 m² Breadth of rectangle same as the side of square Length is 10 m more that it's breadth $\Large{\underline{\mathfrak{\bf{Find}}}}$ Area of rectangle $\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$ We know, $\small\boxed{\sf{\:Area_{square}\:=\:(Side)^2}} \\ \\ \\ \small\sf{\orange{\:\:\:\:\:\:\:\:\star{\:Area_{square}\:=\:1600}}} \\ \\ \\ \mapsto\sf{\:1600\:=\:(side)^2} \\ \\ \\ \mapsto\sf{\:(side)\:=\:\sqrt{1600}} \\ \\ \\ \mapsto\sf{\:Side\:=\:40\:m}$ By first condition:- ( Breadth of rectangle same as the side of square ) So, $\mapsto\sf{\:Breadth_{rectangle}\:=\:side_{square}} \\ \\ \\ \mapsto\sf{\:Breadth_{rectangle}\:=\:40\:m}$ Now, Second condition :- ( Length is 10 m more that it's breadth ) So, $\mapsto\sf{\:Length_{rectangle}\:=\:Breadth_{rectange}\:+\:10} \\ \\ \\ \mapsto\sf{\:Length_{rectangle}\:=\:40+10} \\ \\ \\ \mapsto\sf{\:Length_{rectangle}\:=\:50\:m}$ Again, $\small\boxed{\sf{\:Area_{rectangle}\:=\:(Length\times Breadth)}} \\ \\ \\ \mapsto\sf{\:Area_{rectangle}\:=\:(50\times 40)} \\ \\ \\ \mapsto\sf{\:Area_{rectangle}\:=\:2000\:m^2}$ $\Large{\underline{\mathfrak{\bf{Hence}}}}$ Area of rectangle = 2000 m²

The area of a square is 1600meter square. Find the area of the rectangle whose breadth is the same as that of the square and length is 10m more than its breadth.

Answer»

$\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$

The area of a SQUARE is 1600meter square. FIND the area of the rectangle whose breadth is the same as that of the square and length is 10M more than it's breadth.

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

$\Large{\underline{\mathfrak{\bf{Given}}}}$

Area of square = 1600 m²
Breadth of rectangle same as the side of square
Length is 10 m more that it's breadth

$\Large{\underline{\mathfrak{\bf{Find}}}}$

Area of rectangle

$\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$

We know,

$\small\boxed{\sf{\:Area_{square}\:=\:(Side)^2}} \\ \\ \\ \small\sf{\orange{\:\:\:\:\:\:\:\:\star{\:Area_{square}\:=\:1600}}} \\ \\ \\ \mapsto\sf{\:1600\:=\:(side)^2} \\ \\ \\ \mapsto\sf{\:(side)\:=\:\sqrt{1600}} \\ \\ \\ \mapsto\sf{\:Side\:=\:40\:m}$

By first condition:-

( Breadth of rectangle same as the side of square )

So,

$\mapsto\sf{\:Breadth_{rectangle}\:=\:side_{square}} \\ \\ \\ \mapsto\sf{\:Breadth_{rectangle}\:=\:40\:m}$

Now, Second condition :-

( Length is 10 m more that it's breadth )

So,

$\mapsto\sf{\:Length_{rectangle}\:=\:Breadth_{rectange}\:+\:10} \\ \\ \\ \mapsto\sf{\:Length_{rectangle}\:=\:40+10} \\ \\ \\ \mapsto\sf{\:Length_{rectangle}\:=\:50\:m}$

Again,

$\small\boxed{\sf{\:Area_{rectangle}\:=\:(Length\times Breadth)}} \\ \\ \\ \mapsto\sf{\:Area_{rectangle}\:=\:(50\times 40)} \\ \\ \\ \mapsto\sf{\:Area_{rectangle}\:=\:2000\:m^2}$

$\Large{\underline{\mathfrak{\bf{Hence}}}}$

Area of rectangle = 2000 m²

The area of a square is 1600meter square. Find the area of the rectangle whose breadth is the same as that of the square and length is 10m more than its breadth.

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