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The area of a right angled triangle is 600sqcm if the base of the tri exceeds the altitude by 10cm find dimensions of tri |
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Answer» Answer: Step-by-step explanation: → let the altitude of the triangle =x cm → BASE = (x+10) cm → AREA = 600 sq cm → 1/2× base×altitude = 600 → x(x+10)= 2*600 → x²+10x -1200=0 → x² +40x-30x-1200=0 → x(x+40)-30(x+40)=0 → (x+40)(x-30)=0 → x+40=0 or x-30=0 → x= -40 or x= 30 → x should be negative → x=30 → base = x+10 =30+10=40 → by PYTHAGORAS theorem → hypotenuse square = base square+ altitude square = (40)² + (30)² =1600+900 =2500 → hypotenuse =50 → THREE sides of a triangle → 30cm,40cm and 50cm. |
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