The area of a rectangle is given by A = 6x²y + 4y²x and the width of

1.	The area of a rectangle is given by A = 6x²y + 4y²x and the width of rectangle is w= 2xy. What is the perimeter of rectangle ?
Answer» Answer: area of rectangle= LENGTH×BREADTH =L×B here area,A= 6x²y+4y²x and breadth = W= 2xy LET, length be L then the required equation is: $l \times 2xy = 6 {x}^{2}y + 4 {y}^{2}x \\ l = 6 {x}^{2}y + 4 {y}^{2}x \div 2xy \\ l = 3x + 4y$ HENCE, length of rectangle= 3x+4y perimeter of rectangle= 2(L+B) =2(3x+4y+2xy) 6x+8y+4xy

The area of a rectangle is given by A = 6x²y + 4y²x and the width of rectangle is w= 2xy. What is the perimeter of rectangle ?

Answer»

Answer:

area of rectangle= LENGTH×BREADTH

=L×B

here area,A= 6x²y+4y²x

and breadth = W= 2xy

LET, length be L

then the required equation is:

$l \times 2xy = 6 {x}^{2}y + 4 {y}^{2}x \\ l = 6 {x}^{2}y + 4 {y}^{2}x \div 2xy \\ l = 3x + 4y$

HENCE, length of rectangle= 3x+4y

perimeter of rectangle= 2(L+B)

=2(3x+4y+2xy)

6x+8y+4xy

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The area of a rectangle is given by A = 6x²y + 4y²x and the width of rectangle is w= 2xy. What is the perimeter of rectangle ?​

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The area of a rectangle is given by A = 6x²y + 4y²x and the width of rectangle is w= 2xy. What is the perimeter of rectangle ?