|
Answer» Let the length and breadth of a rectangle be x and y respectively. Area of rectangle = L X B = xy. m^2 CASE I : when length is reduced by 5 m then New length = ( x - 5 ) And, when breadth is increased by 3 m then New breadth = ( y + 3 ) m ====> New Area = ( xy - 9 ) m^2 ( x - 5 ) ( y + 3 ) = xy - 9 xy + 3x - 5y - 15 = xy - 9 3x - 5y - 15 = - 9 3x - 5y = 6 ...................(i) CASE II : When length is increased by 3 m then New length = ( x + 3 ) m And, when breadth is increased by 2 m then New breadth = ( y + 2 ) m ====> New Area = ( xy + 67 ) m^2 ( x + 3 ) ( y + 2 ) = xy + 67 2x + 3y = 61 ....................(ii) Now, Multiply eq. (i) by 3 and eq. (ii) by 5. Then, 9x - 15y = 18 ....................(iii) 10x + 15y = 305 . ................(IV) By adding eq. (iii) and (iv). We get, 19x = 323 x = 17 m ........Answer Hence, The length of rectangle is 17 m.
|