1.

The area of a circle whose sides is a diameter of a circle of area 4s square pi​

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Answer:

Step-by-step explanation:

Given The area of a square WHOSE sides is a DIAMETER of a circle of area 4S square pi

 We know that area of a circle = π r^2

Given area of a circle = 4s^2π

               So π r^2 = 4s^2 π

                 Now r^2 = 4s^2

               So r = 2s

Given diameter = 4s

So area of a square whose side is a diameter will be l^2 = 4s X 4s = 16 s^2


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