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The area between `x=y^2`and `x = 4`is divided into two equal parts by the line`x = a`, find the value of a. |
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Answer» area of first portion=area of second portion `int_0^a(2sqrtx)(dx)=int_a^4(2sqrtx dx` `2(x^(3/2)/(3/2))_0^a=2(x^(3/2)/(3/2))_a^4` `a^(3/2)=4^(3/2)-a^(3/2)` `2a^(3/2)=2^(2*(2/3))` `a=4^(2/3)` |
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